(7-x)^2+(14-x)(7-2x)=(21-x)(7-3x)

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Solution for (7-x)^2+(14-x)(7-2x)=(21-x)(7-3x) equation: 



(7-x)^2+(14-x)(7-2x)=(21-x)(7-3x)

We move all terms to the left:

(7-x)^2+(14-x)(7-2x)-((21-x)(7-3x))=0

We add all the numbers together, and all the variables

(-1x+7)^2+(-1x+14)(-2x+7)-((-1x+21)(-3x+7))=0

We multiply parentheses ..

(+2x^2-7x-28x+98)+(-1x+7)^2-((-1x+21)(-3x+7))=0



We calculate terms in parentheses: -((-1x+21)(-3x+7)), so:

(-1x+21)(-3x+7)

We multiply parentheses ..

(+3x^2-7x-63x+147)

We get rid of parentheses

3x^2-7x-63x+147

We add all the numbers together, and all the variables

3x^2-70x+147

Back to the equation:

-(3x^2-70x+147)



We get rid of parentheses

2x^2-3x^2-7x-28x+(-1x+7)^2+70x+98-147=0

We add all the numbers together, and all the variables

-1x^2+35x+(-1x+7)^2-49=0

We move all terms containing x to the left, all other terms to the right

-1x^2+35x+(-1x+7)^2=49

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